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jokerciker
@jokerciker
July 2022
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log2(5x-1) - (3/(log2(5x-1)-1) + 1= 0
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tays13
Предположим log2 (5x-1)=yy-(3/y-1)+1=0(y+1)=3/y-1y^2-1=3y^2=4y1=+2 y2=-2log2(5x-1)=2 log2(5x-1)=-25x-1=4 5x-1=1/4x=1 x=1/4
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