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rimmabuketova
@rimmabuketova
October 2021
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Лягушка совершает прыжок длинной 2 метра по углом 45 градусов к плоской поверхности. Оприделите длительность прыжка.
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tana20101997
Verified answer
S=V0^2*sin2a/g sin2a=sin(2*45)=1
V0=sqrt(S*g)
S=V0*cosa*t
t=S/sqrt(S*g)*cosa=2/sqrt(2*10) *0,707=0,63 c
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Answers & Comments
Verified answer
S=V0^2*sin2a/g sin2a=sin(2*45)=1V0=sqrt(S*g)
S=V0*cosa*t
t=S/sqrt(S*g)*cosa=2/sqrt(2*10) *0,707=0,63 c