Ответ:
[tex]-4[/tex]
Объяснение:
[tex]\frac{3m+7}{m^2-16}-\frac{m+15}{m^2-16}=\frac{3m+7-m-15}{m^2-16}=\frac{2m-8}{(m-4)(m+4)}=\frac{2(m-4)}{(m-4)(m+4)}=\frac{2}{m+4}\\\\\frac{2}{-4,5+4}=\frac{2}{-0,5}=-\frac{20}{5}=-4[/tex]
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Ответ:
[tex]-4[/tex]
Объяснение:
[tex]\frac{3m+7}{m^2-16}-\frac{m+15}{m^2-16}=\frac{3m+7-m-15}{m^2-16}=\frac{2m-8}{(m-4)(m+4)}=\frac{2(m-4)}{(m-4)(m+4)}=\frac{2}{m+4}\\\\\frac{2}{-4,5+4}=\frac{2}{-0,5}=-\frac{20}{5}=-4[/tex]