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specural
@specural
August 2022
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До пружини, один конец которой закрепён на штативе,повесили груз массой 150 гр.На сколько удлинилась пружина, если её жёсткость 30 Н/м.
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6Sinc
F=k(x2-x1) (или дельта x)
155г=0,15кг.
F=mg=0.15*10=1.5Н
1,5=30x
x=1.5/30=0.05м
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Answers & Comments
155г=0,15кг.
F=mg=0.15*10=1.5Н
1,5=30x
x=1.5/30=0.05м