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nika1299
@nika1299
July 2022
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Матем помогите решить) y=(x^2-19x+19) e^ x+20 найдите точку максимума
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sedinalana
Verified answer
Y`=(2x-19)*e^x+e^x*(x²-19x+19)=e^x*(x²-19x+19+2x-19)=0
x²-17x=0x(x-17)=0
x=0 x=17
+ _ +
-------------------(0)-----------------------(17)------------------
max
ymax=y(0)=(0-0+19)^e=19e
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Answers & Comments
Verified answer
Y`=(2x-19)*e^x+e^x*(x²-19x+19)=e^x*(x²-19x+19+2x-19)=0x²-17x=0x(x-17)=0
x=0 x=17
+ _ +
-------------------(0)-----------------------(17)------------------
max
ymax=y(0)=(0-0+19)^e=19e