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Slavka96
@Slavka96
September 2021
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Методом електроного балансу підібрати коефіцієнти:
Cl2 + NaOH ---> NaCl + NaClO3 + H2O
NaClO3 + MnO2 +NaOH -----> NaCl + Na2MnO4 + H2O
NaCl + MnO2 + H2SO4 ----> Cl2 + MnSO4 + Na2SO4 + H2O
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Darkness21
3Cl2 + 6NaOH ---> 5NaCl + NaClO3 + 3H2O
5 / Cl2^0 + 2e --> 2Cl-
1 / Cl2^0 - 10e --> 2Cl^(+5)
NaClO3 + 3MnO2 + 6NaOH -----> NaCl + 3Na2MnO4 + 3H2O
1 / Cl^(+5) +6e --> Cl^(-1)
3 / Mn^(+4) -2e --> Mn(+6)
2NaCl + MnO2 + 2H2SO4 ----> Cl2 + MnSO4 + Na2SO4 + 2H2O
1 / 2Cl^(-1) -2e --> Cl2^0
1 / Mn^(+4) +2e -->Mn^(+2)
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Answers & Comments
5 / Cl2^0 + 2e --> 2Cl-
1 / Cl2^0 - 10e --> 2Cl^(+5)
NaClO3 + 3MnO2 + 6NaOH -----> NaCl + 3Na2MnO4 + 3H2O
1 / Cl^(+5) +6e --> Cl^(-1)
3 / Mn^(+4) -2e --> Mn(+6)
2NaCl + MnO2 + 2H2SO4 ----> Cl2 + MnSO4 + Na2SO4 + 2H2O
1 / 2Cl^(-1) -2e --> Cl2^0
1 / Mn^(+4) +2e -->Mn^(+2)