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vladislavsuhow
@vladislavsuhow
September 2021
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Решите пожалйста! Рассчитать pH 15% раствора H2SO4( плотность 1,1 г/мл.)
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tomochkasinits
M(H2SO4)р-ра=1000*1,1=1100г;
m(H2SO4)в р-ре=1100*0,15=165г; n(H2SO4)=165/98=1,7моль;
Cм(H2SO4)=1,7моль/л;
H2SO4 -> 2H(+) + SO4(2-)
1,7 3,4
pH= -lg[H+]= -lg3,4(и посмотреть чему равен lg3,4)
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Answers & Comments
m(H2SO4)в р-ре=1100*0,15=165г; n(H2SO4)=165/98=1,7моль;
Cм(H2SO4)=1,7моль/л;
H2SO4 -> 2H(+) + SO4(2-)
1,7 3,4
pH= -lg[H+]= -lg3,4(и посмотреть чему равен lg3,4)