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nikemaxair55780
@nikemaxair55780
July 2022
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egormal2002
CuNO3=64+14+16*3=126
ω(Cu)=64/126*100%=50.79%
ω(N)=14/126*100%=11.11%
ω(O)=48/126*100%=38.1%
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egormal2002
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egormal2002
Cu(NO3)2=64+14*2+16*6=188
ω(Cu)=64/188*100%=34%
ω(N)=28/188*100%=14,9%
ω(O)=96/188*100%=51,1%
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Answers & Comments
ω(Cu)=64/126*100%=50.79%
ω(N)=14/126*100%=11.11%
ω(O)=48/126*100%=38.1%
ω(Cu)=64/188*100%=34%
ω(N)=28/188*100%=14,9%
ω(O)=96/188*100%=51,1%