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Toplit
@Toplit
August 2021
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В смеси угарного и углекислого газа на 5 атомов С приходится 7 атомов кислорода. Определите среднюю молярную массу смеси (в г/моль) с точностью до десятых.
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mrvladimir2
Verified answer
Формула 2СО2*3СО
m(CO2) = 2*44= 88 г
m(CO) = 3*28=84 г
M(2CO2*3CO)= (88 г+84 г)/5 моль=34,4 г/моль
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Verified answer
Формула 2СО2*3СОm(CO2) = 2*44= 88 г
m(CO) = 3*28=84 г
M(2CO2*3CO)= (88 г+84 г)/5 моль=34,4 г/моль