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avarlakhin
@avarlakhin
September 2021
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На оси ординат найдите точку B, отстоящую от точки A(4;−6) на расстояние 5 единиц
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oganesbagoyan
Verified answer
B(0 ; y) ;
---------------
d =AB =√
(
(X(B) -X(A))² +(Y(B) -Y(A))²
);
5 = √
(
(0 -4)² +(y -(-6))²
);
5 = √
(
4² +(y +6)²
);
5² = 4² +(y +6)² ;
5² - 4² =(y +6)² ;
3² =(y +6)² ;
±3 =y+6 ;
[
y+6 =- 3 ;y+6 = 3 .
y = - 9
или
y = -3 .
11 votes
Thanks 20
avarlakhin
спасибо
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Answers & Comments
Verified answer
B(0 ; y) ;---------------
d =AB =√( (X(B) -X(A))² +(Y(B) -Y(A))² );
5 = √( (0 -4)² +(y -(-6))² );
5 = √( 4² +(y +6)² );
5² = 4² +(y +6)² ;
5² - 4² =(y +6)² ;
3² =(y +6)² ;
±3 =y+6 ;
[ y+6 =- 3 ;y+6 = 3 .
y = - 9 или y = -3 .