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akp99
@akp99
August 2022
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На рисунке изображены графики функций y = 6 − x2 и y = − x. Вычислите абсциссу точки B.
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ShirokovP
Verified answer
6 - x^2 = - x
x^2 - x - 6 = 0
D = 1 + 24 = 25 = 5^2
x1 = (1 + 5)/2 = 6/2 = 3
x2 = (1 - 5)/2 = - 4/2 = - 2
Абсцисса точки B = 3
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Answers & Comments
Verified answer
6 - x^2 = - xx^2 - x - 6 = 0
D = 1 + 24 = 25 = 5^2
x1 = (1 + 5)/2 = 6/2 = 3
x2 = (1 - 5)/2 = - 4/2 = - 2
Абсцисса точки B = 3