Найди множество корней уравнения (x - 2)^2 - 9 = 0 (2x + 1)^2 - (x - 1)^2 = 0. Created by nikolas2000. algebra-ru

Найди множество корней уравнения (x - 2)^2 - 9 = 0 (2x + 1)^2 - (x

nikolas2000 @nikolas2000

August 2022 1 3 Report

Найди множество корней уравнения
(x - 2)^2 - 9 = 0
(2x + 1)^2 - (x - 1)^2 = 0

Answers & Comments

Gviona 1). (x-2)^2-9=0
(x-2)^2-3^2=0
(x-2-3)(x-2+3)=0
(x-5)(x+1)=0
x-5=0 x+1=0
x=5 x=-1

2).(2x+1)^2-(x-1)^2=0
(2x+1-x+1)(2x+1+x-1)=0
(x+2) *3x=0
x+2=0 3x=0
x=-2 x=0

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najdite znachenie vyrazheniya 124 2563

razlozhite na mnozhiteli 42a 12 9a2 25x2 163x 52

predstavte v vide proizvedeniya 1 0125m3 razlozhite na mnozhiteli 2x y3

gidravlicheskij press dayot vyigrysh v sile v 12 raz kakaya sila budet dejstvovat679836866aa8efac83bfb53e21293a0f 21273

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