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tsukhaya
@tsukhaya
August 2022
1
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Найди значение выражения( дробь) при x=7
x2(квадрат)+x+1 - 4x+24
x3( в кубе)−125 125−x3( в кубе) при x=7
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mari1901
49+7+1-28+24=54
343-125 =218
125-343=-218
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tsukhaya
какая дробь?
mari1901
стоп, обьясни...
mari1901
у тебя между -125 и 125 ничего нету... так должно быть?
tsukhaya
смотри 1 дробь - вторая
tsukhaya
дробь 1 - вторая
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Answers & Comments
343-125 =218
125-343=-218