Найдите количество целых корнейsqrt(2x+1)

m672 @m672

July 2022 1 4 Report

Найдите количество целых корней

sqrt(2x+1) - sqrt(x-3) = sqrt(x-8)

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Матов

Verified answer

$x-8=a\\
x-3=a+5\\
2x+1=2a+17\\\\
\sqrt{2a+17}=\sqrt{a}+\sqrt{a+5}\\
2a+17=2a+5+2\sqrt{a^2+5a}\\
6=\sqrt{a^2+5a}\\
a^2+5a-36=0\\
D=13^2\\
a=4\\
x=12$
Ответ $12$

2 votes Thanks 1

Матов да

zadanie v prilozhenii nuzhno obyasnit formu takoj zapisi chisla i podrobnee obyas

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m672 August 2022 | 0 Ответы

a^2)...

Answer

m672 August 2022 | 0 Ответы

x = 3...

Answer

m672 August 2022 | 0 Ответы

5 i 5a b 2c 28

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m672 August 2022 | 0 Ответы

40 odnogo chisla ravno 60 drugogo chisla najti chisla esli summa ih sostavlyaet

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m672 August 2022 | 0 Ответы

x38y3ya tak ponimayu chto vtoroe nuzhno nahodit po formule sokrashennogo umnozh8ac9d1efe52533969d4f8c784376c5e4 42022

Answer

Answers & Comments

Verified answer

sqrt77757790 7770 7795 kak eto reshaetsya bez aktualnogo umnozheniya etih chi

x 8 sqrt60 najti sqrtx sqrt3

vychislite summu kornej uravneniya sm vlozhenie2 najti raznost ar j progressi

zadacha na procenty na skolko procentov nuzhno umenshit storony odnogo kvadrata

zadanie v prilozhenii nuzhno obyasnit formu takoj zapisi chisla i podrobnee obyas

a^2)...

x = 3...

5 i 5a b 2c 28

40 odnogo chisla ravno 60 drugogo chisla najti chisla esli summa ih sostavlyaet

x38y3ya tak ponimayu chto vtoroe nuzhno nahodit po formule sokrashennogo umnozh8ac9d1efe52533969d4f8c784376c5e4 42022

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