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DIkariLLi
@DIkariLLi
October 2021
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найдите корни трехчлена хквадрат-8х+7,хквадрат-8х+15
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Таня1888
1)х²-8х+7=0
D=b²-4ac=(-8)²-4*7=64-28=36=6²
x1=8-6/2=1
x2=8+6/2=7
корни 1 и 7
2) х²-8х+15=0
(-8)²-4*15=4=2²
х1=8-2/2=3
х1=8+2/2=5
корни 3 и 5
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Answers & Comments
D=b²-4ac=(-8)²-4*7=64-28=36=6²
x1=8-6/2=1
x2=8+6/2=7
корни 1 и 7
2) х²-8х+15=0
(-8)²-4*15=4=2²
х1=8-2/2=3
х1=8+2/2=5
корни 3 и 5