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DIkariLLi
@DIkariLLi
October 2021
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Разложите на множители квадратный трехчлен 6хквадрат-5х+1,12хквадрат+5х-2
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nafanya2014
Verified answer
6х²+5х+1=0
D=5²-4·6=25-24=1
x₁=(-5-1)/12=-6/12=-1/2 или x₂=(-5+1)/12=-4/12=-1/3
ax²+bx+c=a·(x-x₁)(x-x₂)
6х²+5х+1=6·(x-(-1/2))·(x-(-1/3))
6х²+5х+1=2·3·(x+(1/2))·(x+(1/3))
6х²+5х+1=3·(2x+1)·(3x+1)
12х²+5х-2=0
D=25-4·12·(-2)=25+96=121
x₁=(-5-11)/24=-16/24=-4/6=-2/3 x₂=(-5+11)/24=6/24=1/4
12х²+5х-2=12·(x-(-2/3))·(x-(1/4))
12x²+5x-2=(3x+2)·(4x-1)
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Answers & Comments
Verified answer
6х²+5х+1=0D=5²-4·6=25-24=1
x₁=(-5-1)/12=-6/12=-1/2 или x₂=(-5+1)/12=-4/12=-1/3
ax²+bx+c=a·(x-x₁)(x-x₂)
6х²+5х+1=6·(x-(-1/2))·(x-(-1/3))
6х²+5х+1=2·3·(x+(1/2))·(x+(1/3))
6х²+5х+1=3·(2x+1)·(3x+1)
12х²+5х-2=0
D=25-4·12·(-2)=25+96=121
x₁=(-5-11)/24=-16/24=-4/6=-2/3 x₂=(-5+11)/24=6/24=1/4
12х²+5х-2=12·(x-(-2/3))·(x-(1/4))
12x²+5x-2=(3x+2)·(4x-1)