Найдите корни уравнения:(x²-2x-1)²-11(x²-2x+1)+30=0. Created by NastyaLittle. algebra-ru

Найдите корни уравнения:(x²-2x-1)²-11(x²-2x+1)+30=0...

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(x²-2x-1)²-11(x²-2x+1)+30=0
x2-2x-1=t
t2-11t+30=0
t12=(11+-корень(121-120))/2=(11+-1)/2= 5 6
x2-2x-1=5
x2-2x-6=0
x12=(2+-корень(4+24))/2=(2+-корень(28))/2=1+-корень(7)
x2-2x-1=6
x2-2x-7=0
x34=(2+-корень(4+28))/2=(2+-корень(32))/2=1+-корень(8)

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