y=x2x +2
найдем производную
y'=(x2x +2)'=x2
(x·x2)' = (x)'·x2+x·(x2)' = 1·x2+x·0
Ответ: x2
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y=x2x +2
найдем производную
y'=(x2x +2)'=x2
(x·x2)' = (x)'·x2+x·(x2)' = 1·x2+x·0
Ответ: x2