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weronica
@weronica
July 2022
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Найдите массу воды, которая образуется при соединении 44,8 л водорода с кислородом. (формула: 2Н2 + О2 = 2Н2О)
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ndambaeva
44.8L xg
2H2+O2=2H2O
44.8L 36g
x=44.8*36/44.8=36g
2 votes
Thanks 6
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Answers & Comments
2H2+O2=2H2O
44.8L 36g
x=44.8*36/44.8=36g