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sofiya10062002
@sofiya10062002
October 2021
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Найдите наименьшее общее кратное чисел : 1) 42 и 63. 2) 120 и 324. 3) 675 и 945. 4) 924 и 396.
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Удачник66
Verified answer
НОК(42, 63) = НОК(6*7, 9*7) = 2*9*7 = 126
НОК(120, 324) = НОК(8*3*5, 4*81) = 8*81*5 = 3240
НОК(675, 945) = НОК(27*25, 27*5*7) = 27*25*7 = 4725
НОК(924, 396) = НОК(4*3*7*11, 4*9*11) = 4*9*7*11 = 2772
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Answers & Comments
Verified answer
НОК(42, 63) = НОК(6*7, 9*7) = 2*9*7 = 126НОК(120, 324) = НОК(8*3*5, 4*81) = 8*81*5 = 3240
НОК(675, 945) = НОК(27*25, 27*5*7) = 27*25*7 = 4725
НОК(924, 396) = НОК(4*3*7*11, 4*9*11) = 4*9*7*11 = 2772