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BlackOwl
@BlackOwl
July 2022
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найдите область определения функции √3x-x^2
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ShirokovP
Verified answer
D(y)= [ 0; 3 ]
Решим нестрогое неравенство:
3x - x^2 ≥ 0
- x^2 + 3x ≥ 0
x^2 - 3x ≤ 0
x (x - 3) ≤ 0
x ∈ [ 0; 3 ]
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Answers & Comments
Verified answer
D(y)= [ 0; 3 ]Решим нестрогое неравенство:
3x - x^2 ≥ 0
- x^2 + 3x ≥ 0
x^2 - 3x ≤ 0
x (x - 3) ≤ 0
x ∈ [ 0; 3 ]