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yurashchiyan
@yurashchiyan
July 2022
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найдите область определения функции
f (x) = √2x ^ 2 + 12
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ShirokovP
Verified answer
2x^2 + 12 >= 0 /:2
x^2 + 6 >= 0
x^2 + 6 = 0
D = 0 - 24 < 0
D(y) = ( - ∞; + ∞)
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Answers & Comments
Verified answer
2x^2 + 12 >= 0 /:2x^2 + 6 >= 0
x^2 + 6 = 0
D = 0 - 24 < 0
D(y) = ( - ∞; + ∞)