Найдите область определения функции:. Created by luhxor. algebra-ru

Найдите область определения функции:...

luhxor @luhxor

November 2021 1 33 Report

Найдите область определения функции:

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TARTILLO

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Область определения функции y=√[√(6+7x-3x²)/(-3x²+2x+8)]

(6+7x-3x²)≥0
(-3x²+2x+8)>0
- + -
1) (6+7x-3x²)≥0 ----------(-2/3)//////////////////////(3)-------
3x²-7x-6=0
D=49+4·3·6=121=11²
x1=-2/3
x2=3
----------[-2/3)/////////////////////////////(3]-------
- + -
2)(-3x²+2x+8)>0 ------(-4/3)/////////////////////////////(2)------------
3x²-2x-8=0
D=4+4·3·8=100=11²
x1=(2-10)/6=-4/3
x2=12/6=2

т.о область определения функции y=√[√(6+7x-3x²)/(-3x²+2x+8)]
x∈[-2/3; 2)

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