Ответ:

1. f'(x)=(1/3)*3x^2-2x+2=3x^2-2x+2

2.f'(x)=(2*x^(-3)'-(x^1.5)'=-2*3*x^(-4)-1,5√x=-6x^(-4)-1.5√x

3. f'(x}=4cosx(sinx)'+4sinx(cosx)'=4cos^2x-4sin^2x=4(cos^2x-sin^2x)=

=4cos4x; f'(-2П/3)=4cos(-8П/3)=4cos(-2П/3)=4cos(2П/3)=-4cosП/3=-2

4, f'(x)=((2-3x)'(x+2)-(x+2)'(2-3x))/(x+2)^2=

=(-3(x+2)-(2-3x))/(x+2)^2=(-3x-6-2+3x)/(x+2)^2=-8/(x+2)^2

f'(-1)=-8/(-1+2)^2=-8

5. f'(x)=x^2-4

x^2-4=0  x=2 x=-2

Объяснение: