Verified answer

lim(x->2, y->-2) (y^2 + 5y + 6)(x- 1)/(x^2 + x - 2)(y + 2) = ******

разложим многочлены

ну от x ничего не зависит , наверное x -> 1

y^2 + 5y + 6 = (y + 2)(y + 3)

D = 5^2 - 24 = 1

y12=(-5+-1)/2 = -2  -3

x^2 + x - 2 = (x + 2)(x - 1)

D = 1 + 8 = 9

x12 = (-1 +- 3)/2 = -2   1

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***** = lim(x->2, y->-2) (y + 2)(y + 3)(x - 1)/(y + 2)(x + 2)(x - 1) = lim(x->2, y->-2) (y + 3)/(x + 2) = (-2 + 3)/(2 + 2) = -1/4