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KonorEcio
@KonorEcio
July 2022
2
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найдите , при каком значении аргумента...
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sedinalana
Verified answer
(x-1)/(x-2)-3x/(x+2)=1/2
x≠2,x≠-2
2(x-1)(x+2)-6x(x-2)=x²-4
2x²+4x-2x-4-6x²+12x-x²+4=0
-5x²+14x=0
-x(5x-14)=0
x=0
x=2,8
1 votes
Thanks 1
hraky
D(f): х ≠ -2 и х ≠ 2
(х-1)/(х-2) - (3х)/(х+2) =1/2
(х-1)(х+2)-3х(х-2)=(х²-4)/2
(х²+2х-х-2)-3х²+6х=(х²-4)/2
-2х²+7х-2=(х²-4)/2
-4х²+14х-4=х²-4
5х²-14х=0
х₁=0
х₂=14/5=2,8
Ответ: х₁=0 х₂=2,8
1 votes
Thanks 1
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Answers & Comments
Verified answer
(x-1)/(x-2)-3x/(x+2)=1/2x≠2,x≠-2
2(x-1)(x+2)-6x(x-2)=x²-4
2x²+4x-2x-4-6x²+12x-x²+4=0
-5x²+14x=0
-x(5x-14)=0
x=0
x=2,8
(х-1)/(х-2) - (3х)/(х+2) =1/2
(х-1)(х+2)-3х(х-2)=(х²-4)/2
(х²+2х-х-2)-3х²+6х=(х²-4)/2
-2х²+7х-2=(х²-4)/2
-4х²+14х-4=х²-4
5х²-14х=0
х₁=0
х₂=14/5=2,8
Ответ: х₁=0 х₂=2,8