найдите производную ф-ции
а)f(x)=cos(5-2x)+ctgx
б)f(x)=sinx*cos(2x-3)
F(x)= sin5-sin2x+Tgx
F(x)=ctg2x-ctg3
a) y=cos(5-2x)+ctgx
y' = sin2x - 1/sin^2x
б) y=sinx*cos(2x-3)
y' = cosx* cos(2x-3) - 2sin(2x-3)*sinx
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
F(x)= sin5-sin2x+Tgx
F(x)=ctg2x-ctg3
a) y=cos(5-2x)+ctgx
y' = sin2x - 1/sin^2x
б) y=sinx*cos(2x-3)
y' = cosx* cos(2x-3) - 2sin(2x-3)*sinx