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kseniyaxudyako
@kseniyaxudyako
August 2022
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Найдите производные функций при данном значении аргумента:
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dasdasfa
F'(z)=(1/cos^2 (4z) )*(cos^2 (4z)'=(1/cos^2 (4z) )*2cos4z*(cos4z)'=
=(1/cos^2 (4z) )*2cos4z*(-4sin 4z))=-8sin4z/cos4z=-8tg4z
Fπ/16)=-8tg(4*π/16)=-8tg π/4=-8*1=-8
2) f'(t)=8cost*cos' t=-8costsint=-4sin2t
f'(π/4)=-4sin(2*π/4)=-4sinπ/2=-4
1 votes
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kseniyaxudyako
Спасибо большое :)
kseniyaxudyako
Не смог(ла) бы решить вторую часть? http://znanija.com/task/20039113
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Answers & Comments
=(1/cos^2 (4z) )*2cos4z*(-4sin 4z))=-8sin4z/cos4z=-8tg4z
Fπ/16)=-8tg(4*π/16)=-8tg π/4=-8*1=-8
2) f'(t)=8cost*cos' t=-8costsint=-4sin2t
f'(π/4)=-4sin(2*π/4)=-4sinπ/2=-4