sedinalana

Verified answer

1
ОДЗx>0
log(30x-2log(1/3)x=6
log(3)x+2log(3)x=6
3log(3)x=6
log(3)x=2
x=9
2
ОДЗ
x+1>0
x>-1
log(5)(x²+8)-log(5)(x+1)=3log(5)2
log(5)[(x²+8)/(x+1)]=log(5)8
(x²+8)/(x+1)=8
x²+8=8x+8
x²-8x=0
x(x-8)=0
x=0
x-8=0
x=8