Home
О нас
Products
Services
Регистрация
Войти
Поиск
Петрушка15
@Петрушка15
July 2022
2
7
Report
Найдите производные функций:
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
sedinalana
A
y`=[1/2√*(x²+3)-2x*(√x+1)]/(x²+3)²=(x²+3-4x²-4x²+3)²]=(3-4x√x-3x²)/[х²+3)²]
b
y`=1/2√(4x²-x+11) *(8x-1)=(8x-1)/2√(4x²-x+11)
0 votes
Thanks 0
Змей24
A) y` = (sqrt(x)/(x^2 + 3))` + (1/(x^2 + 3))` = (0.5/sqrt(x) * (x^2 + 3) - 2x*sqrt(x))/((x^2 + 3)^2) - 2x/(x*x+3)^2 = (0.5/sqrt(x) * (x^2 + 3) - 2x*sqrt(x) - 2x)/((x^2 + 3)^2).
б) 0.5/sqrt(4*x*x-x+11)*(8x-1)
0 votes
Thanks 0
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "Найдите производные функций:..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
y`=[1/2√*(x²+3)-2x*(√x+1)]/(x²+3)²=(x²+3-4x²-4x²+3)²]=(3-4x√x-3x²)/[х²+3)²]
b
y`=1/2√(4x²-x+11) *(8x-1)=(8x-1)/2√(4x²-x+11)
б) 0.5/sqrt(4*x*x-x+11)*(8x-1)