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luba2111
@luba2111
July 2022
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Найдите произвольную функцию: y=(√3x+5)
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ЮрВас
Y⁽=[(3x+5)^1/2]⁽=(1/2)(3x+5)^-1/2*3=
=(3/2)*1/(
√3x+5)
1 votes
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Answers & Comments
=(3/2)*1/(√3x+5)