найдите решение системы уравнений способом подстановки
1) 5х-2(у+4)=0
6(2х+3)-у=41
2) 2х+3(х+4)=11
7(х+3у)-6х=-59
x=2(y+4)/5
6(4(y+4)/5+3)-y=41
6(4y+16+15)-5y=205
24y+64+90-5y=205
24y+154-5y=205
y=1
x=2
2x+3x+12=11
7x+ 21y-6x = - 59
x=-1/5
-7/5+21y-6/5 = -59
21y= -59+13/5
y = -282/105
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Verified answer
x=2(y+4)/5
6(4(y+4)/5+3)-y=41
6(4y+16+15)-5y=205
24y+64+90-5y=205
24y+154-5y=205
y=1
x=2
2x+3x+12=11
7x+ 21y-6x = - 59
x=-1/5
-7/5+21y-6/5 = -59
21y= -59+13/5
y = -282/105