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welcome124
@welcome124
July 2022
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Найдите решения неравенства x²+ 4x>0
1) 0<х<4
2) -4<х<0
3) х>0
4) х<-4; х>0
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Verified answer
x²+ 4x>0
х(х+4)>0
+ - +
_________-4________________0_____________
x<-4 x>0
Ответ: 4)
2 votes
Thanks 3
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Verified answer
x²+ 4x>0х(х+4)>0
+ - +
_________-4________________0_____________
x<-4 x>0
Ответ: 4)