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kkristina280900
@kkristina280900
July 2022
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найдите sin(a) если cos(a) 3√11 и a€(0;0,5п)
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kmike21
Verified answer
Sin²a+cos²a=1, поэтому sin²a=1-cos²a=1-(3/√11)²=1-9/11=(11-9)/11=2/11
при a∈(0;0,5π) sina>0, поэтому sina=√2/√11
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kkristina280900
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Verified answer
Sin²a+cos²a=1, поэтому sin²a=1-cos²a=1-(3/√11)²=1-9/11=(11-9)/11=2/11при a∈(0;0,5π) sina>0, поэтому sina=√2/√11