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Zeya1
@Zeya1
August 2021
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найдите среднюю квадратичную скорость молекул азота при температуре 27°C
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keelerman90909
V= корень кв(3*R*T/V)= корень кв(3*8,31*300/28*10^-3)=516,7м/с
2 votes
Thanks 2
Zeya1
по какой формуле решать?
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