Найдите сумму: 1) 12целых 3\8 +8целых 1\6 2) 3целых 13\15 + 6целых 7\10 3) 9целы...

August 2021 1 34 Report

Найдите сумму:
1) 12целых 3\8 +8целых 1\6
2) 3целых 13\15 + 6целых 7\10
3) 9целых 8\21 + 4целых 11\14
4) 8целых 5\9 +7целых 3\4 +12 целых 7\12

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Ответ:

$\tt \displaystyle 1) \; 12\frac{3}{8}+8\frac{1}{6}=12+8+\frac{3}{8}+\frac{1}{6}=20+\frac{3\cdot 3}{8 \cdot 3}+\frac{1 \cdot 4}{6\cdot 4}=\\\\=20+\frac{9}{24}+\frac{4}{24}=20+\frac{9+4}{24}=20+\frac{13}{24}=20\frac{13}{24}$

$\tt \displaystyle 2) \; 3\frac{13}{15}+6\frac{7}{10}=3+6+\frac{13}{15}+\frac{7}{10}=9+\frac{13\cdot 2}{15 \cdot 2}+\frac{7 \cdot 3}{10\cdot 3}=\\\\=9+\frac{26}{30}+\frac{21}{30}=9+\frac{26+21}{30}=9+\frac{47}{30}=9+1+\frac{17}{30}=10\frac{17}{30}$

$\tt \displaystyle 3) \; 9\frac{8}{21}+4\frac{11}{14}=9+4+\frac{8}{21}+\frac{11}{14}=13+\frac{8\cdot 2}{21 \cdot 2}+\frac{11 \cdot 3}{14\cdot 3}=13+\frac{16}{42}+\frac{33}{42}=\\\\=13+\frac{16+33}{42}=13+\frac{49}{42}=13+1+\frac{7}{42}=14+\frac{7:7}{42:7}=14+\frac{1}{6}=14\frac{1}{6}$

$\tt \displaystyle 4) \; 8\frac{5}{9}+7\frac{3}{4}+12\frac{7}{12}=8+7+12+\frac{5}{9}+\frac{3}{4}+\frac{7}{12}=\\\\=27+\frac{5 \cdot 4}{9 \cdot 4}+\frac{3 \cdot 9}{4 \cdot 9}+\frac{7 \cdot 3}{12 \cdot 3}=27+\frac{20}{36}+\frac{27}{36}+\frac{21}{36}=27+\frac{20+27+21}{36}=\\\\=27+\frac{68}{36}=27+1+\frac{32}{36}=28+\frac{32:4}{36:4}=28+\frac{8}{9}=28\frac{8}{9}$

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