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Veronikanast
@Veronikanast
July 2022
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Найдите сумму первых 12 членов арифметической прогрессии (аn), если а12 = 36, d=3
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akaramova93
Ответ: a1=36-3*11=3
s12=(3+36)12/2=234
2 votes
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Answers & Comments
Ответ: a1=36-3*11=3
s12=(3+36)12/2=234