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antoniy830
@antoniy830
July 2022
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Найдите
tgα , если sinα = − √ 51 10 и α ∈ ( 3π 2;2 π) .
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kunnei2
А лежит в 4 четверти значит косинус положительный
cos a=корень из (1-51/100)=корень из (49/100)=7/10
tg a=-|/51/10÷7/10=-|/51/7
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antoniy830
То есть cos полож, tg будет отрицательный?
kunnei2
да, так как синус отрицательный
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Answers & Comments
cos a=корень из (1-51/100)=корень из (49/100)=7/10
tg a=-|/51/10÷7/10=-|/51/7