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mishah03
@mishah03
August 2022
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Найдите значения выражения.
4a²(x+7)+3(x+7) при a= -0.5 x= -1,05.
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Асик777Асик
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4а²(х+7)+3(х+7)=(х+7)(4а²+3)=(-1,05+7)(4*(-0,5)²+3)=5,95(4*0,25+3)=5,95(1+3)=5,95*4=23,8.
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4а²(х+7)+3(х+7)=(х+7)(4а²+3)=(-1,05+7)(4*(-0,5)²+3)=5,95(4*0,25+3)=5,95(1+3)=5,95*4=23,8.