Решите уравнения 4y²-25=0 (6x-1)²-(3x-5)²=0. Created by mishah03. algebra-ru

4y²-25=04y²=25y²= (6x-1)²-(3x-5)²=027x² + 18x - 24 =03(3x-2)(3x+4)=0 (3x-2)(3x+4)=03x-2=0 3x+4=03x=2 3x=-4

Решите уравнения 4y²-25=0 (6x-1)²-(3x-5)²=0...

August 2022 1 10 Report

Решите уравнения
4y²-25=0
(6x-1)²-(3x-5)²=0

Answers & Comments

Munkush 4y²-25=0
4y²=25
y²= $\frac{25}{4}$

$y=б2.5$

(6x-1)²-(3x-5)²=0
27x² + 18x - 24 =0
3(3x-2)(3x+4)=0
(3x-2)(3x+4)=0
3x-2=0 3x+4=0
3x=2 3x=-4
$x =\frac{2}{3}$ $x= -\frac{4}{3}$

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