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drondront11
@drondront11
December 2021
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Найдитикорни квадратного трёхчлена.
x^2+5x+6
2x^2-18
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3ann38
X^2+5x+6=0
D=b^2-4ac=5^2-4*1*6=25-24=1
x1= -b+корень из D/2а
х2= -b-корень из D/2a
x1= -5+1 /2 = -2
x2= -5-1 /2 = -2
Ответ: -2
2x^2-18=0
D= b^2-4ac= 0-4*2*(-18)= 144
x1= 0+12 /2*2 = 3
x2= 0-12 /2*2 = -3
Ответ: 3; -3
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Answers & Comments
D=b^2-4ac=5^2-4*1*6=25-24=1
x1= -b+корень из D/2а
х2= -b-корень из D/2a
x1= -5+1 /2 = -2
x2= -5-1 /2 = -2
Ответ: -2
2x^2-18=0
D= b^2-4ac= 0-4*2*(-18)= 144
x1= 0+12 /2*2 = 3
x2= 0-12 /2*2 = -3
Ответ: 3; -3