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drondront11
@drondront11
October 2021
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Решите неравества 76-78
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gorshckowashur
Решение:
а)x^2+3x-4(больше либо равно)>/0
Приравняем к нулю:
X^2+3X-4=0
D=(-3)^2+4*4=25
X1,2=(-b(+-)_/D)/2a
X1=-3+5/2=1
X2=-3-5/2=-4
X^2+3X-4=(X-1)(X+4)
(X-1)(X+4)>/0
////// /////////////
----.(-4)---------.(1)---------->
- _
|_-бесконечности;-4 _|
_ _
|_1;+бесконечности_|
б)x^2+10x+25/<0
(х+5)^2/<0
x/<-5
///////////
--------.(-5)------------->
_
(-бесконечности;-5_|
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Answers & Comments
а)x^2+3x-4(больше либо равно)>/0
Приравняем к нулю:
X^2+3X-4=0
D=(-3)^2+4*4=25
X1,2=(-b(+-)_/D)/2a
X1=-3+5/2=1
X2=-3-5/2=-4
X^2+3X-4=(X-1)(X+4)
(X-1)(X+4)>/0
////// /////////////
----.(-4)---------.(1)---------->
- _
|_-бесконечности;-4 _|
_ _
|_1;+бесконечности_|
б)x^2+10x+25/<0
(х+5)^2/<0
x/<-5
///////////
--------.(-5)------------->
_
(-бесконечности;-5_|