∫√(2x-3)dx=(1/2)∫t^(1/2)dt=(1/2)*(2t^(3/2))/3=(t^(3/2))/3=((2x-3)^(3/2))/3+C
2x-3=t 2dx=dt dx=(1/2)dt
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∫√(2x-3)dx=(1/2)∫t^(1/2)dt=(1/2)*(2t^(3/2))/3=(t^(3/2))/3=((2x-3)^(3/2))/3+C
2x-3=t 2dx=dt dx=(1/2)dt