∫√(x³+1)x²dx=1/3∫t^(1/2)dt=(1/3)*2t^(3/2)/3=(2/9)(x³+1)^(3/2)+C
x³+1=t 3x²dx=dt x²dx=(1/3)dt
∫e⁵ˣ⁺³dx=(1/5)e⁵ˣ⁺³+C
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∫√(x³+1)x²dx=1/3∫t^(1/2)dt=(1/3)*2t^(3/2)/3=(2/9)(x³+1)^(3/2)+C
x³+1=t 3x²dx=dt x²dx=(1/3)dt
∫e⁵ˣ⁺³dx=(1/5)e⁵ˣ⁺³+C