Ответ:
∫(x^(-1/3)+x^(3/2)+2)dx=(x^(2/3)/(2/3)+x^(5/2)/(5/2)+2x=3x^(2/3)/2+2x^(5/2)/5+2x+C
∫(x³+1)²dx=∫(x⁶+2x³+1)dx=x⁷/7+2x⁴/4+x
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Verified answer
Ответ:
∫(x^(-1/3)+x^(3/2)+2)dx=(x^(2/3)/(2/3)+x^(5/2)/(5/2)+2x=3x^(2/3)/2+2x^(5/2)/5+2x+C
∫(x³+1)²dx=∫(x⁶+2x³+1)dx=x⁷/7+2x⁴/4+x