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ZumbaLover
@ZumbaLover
July 2022
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Найти наибольшее значение функции f(x)=3x^2 - 4x - 4 на отрезке [0;3]. Введите числовой ответ.
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mikael2
Verified answer
F(x)=3x²-4x-4
f(0)=-4
f(3)=27-12-4=11
f'(x)=6x-4 6x-4=0 x=2/3
f(2/3)=3*4/9-4*2/3-4=12/9-24/9-4<0<11
наибольшее значение 11
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Answers & Comments
Verified answer
F(x)=3x²-4x-4f(0)=-4
f(3)=27-12-4=11
f'(x)=6x-4 6x-4=0 x=2/3
f(2/3)=3*4/9-4*2/3-4=12/9-24/9-4<0<11
наибольшее значение 11