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palaver8
@palaver8
June 2021
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Найти область определения функции:
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kirichekov
Verified answer
ОДЗ: (x²-1)>0
(x-1)(x+1)>0
1. x-1=0 или x-1=0
2. x=0, 0∈(-1;1). (0-1)(0+1)=-1, -1<0
(x-1)(x+1)<0, если х∈(-1;1)
+ - +
----------------|------------|-------------->x
-1 1
ответ: x⇔(-∞;-1)U(1;∞)
2 votes
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Answers & Comments
Verified answer
ОДЗ: (x²-1)>0(x-1)(x+1)>0
1. x-1=0 или x-1=0
2. x=0, 0∈(-1;1). (0-1)(0+1)=-1, -1<0
(x-1)(x+1)<0, если х∈(-1;1)
+ - +
----------------|------------|-------------->x
-1 1
ответ: x⇔(-∞;-1)U(1;∞)