Найти область значений функции y=2-корень из {x^2+2x+1}. Created by BlackberryStorm. algebra-ru

Найти область значений функции y=2-корень из {x^2+2x+1}...

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July 2022 1 10 Report

Найти область значений функции y=2-корень из {x^2+2x+1}

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$y=2-\sqrt{x^2+2x+1}\\x^2+2x+1=(x+1)^2, \sqrt{(x+1)^2}=|x+1|\\y=2-|x+1|\\y-2=-|x+1|\\Takkak|x+1| \geq 0,to(-|x+1|) \leq 0,togda\\y-2 \leq 0, y \leq 2\\y\in (-\infty,2]$

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