f (x) = ∫ F (x) dx = ∫ (4 * sin x + cos (3 * x)) dx = ∫ 4 * sin x dx + ∫ cos (3 * x) dx = 4 * ∫ sin x dx + 1/3 * ∫ cos (3 * x) d (3 * x) = 4 * (-cos x) + 1/3 * sin (3 * x) + C = -4 * cos x + 1/3 * sin (3 * x) + C;
F (x) = 4 * sin x + cos (3 * x) равна f (x) = -4 * cos x + 1/3 * sin (3 * x) + C.
Answers & Comments
F (x) = 4 * sin x + cos3x равна
f (x) = ∫ F (x) dx = ∫ (4 * sin x + cos (3 * x)) dx = ∫ 4 * sin x dx + ∫ cos (3 * x) dx = 4 * ∫ sin x dx + 1/3 * ∫ cos (3 * x) d (3 * x) = 4 * (-cos x) + 1/3 * sin (3 * x) + C = -4 * cos x + 1/3 * sin (3 * x) + C;
F (x) = 4 * sin x + cos (3 * x) равна f (x) = -4 * cos x + 1/3 * sin (3 * x) + C.
я не знаю как решить б) сорри