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redst0n4
@redst0n4
July 2022
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найти у' если
y=x^2+sin3x
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spasibo3pajbrh
Y'(x)= (x²+sin3x)'=
=(x²)'+(sin3x)'=
=2x+cos3x•(3x)'=
=2x+3cos3x
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Answers & Comments
=(x²)'+(sin3x)'=
=2x+cos3x•(3x)'=
=2x+3cos3x